问道10速坐骑的坐骑有没有9+1和我10+1的?

1.(1/2+1/3+1/4+1/5)*(1/3+1/4+1/5+1/6)-(1/2+1/3+1/4+5/1+1/6)*(1/3+1/4+1/5)=?简便运算2.(1/8+1/9+1/10+1/11)*(1/9+1/10+1/11+1/12)-(1/8+1/9+1/10+1/11+1/12)*(1/9+1/10+1/11)=?简便运算3.(1+1/0+1/2001)*(1/0+1/2)-(1+_百度作业帮
1.(1/2+1/3+1/4+1/5)*(1/3+1/4+1/5+1/6)-(1/2+1/3+1/4+5/1+1/6)*(1/3+1/4+1/5)=?简便运算2.(1/8+1/9+1/10+1/11)*(1/9+1/10+1/11+1/12)-(1/8+1/9+1/10+1/11+1/12)*(1/9+1/10+1/11)=?简便运算3.(1+1/0+1/2001)*(1/0+1/2)-(1+1/0+1/2)*(1/0+1/2001)=?简便运算
1、令1/2+1/3+1/4+1/5+1/6=a;则原式可变为:(a-1/6)(a-1/2)-a(a-1/2-1/6)=a*a-a2/3+1/12-a*a+a2/3=1/12.2、令1/8+1/9+1/10+1/11+1/12=a;则原式可变为:(a-1/12)(a-1/8)-a(a-1/8-1/12)=a*a-a5/24+1/96-a*a+a5/24=1/96.3、令1+1/0+1/2=a;则原式可变为:(a-1/2002)(a-1)-a(a-1-1/2002)=1/2002.
您可能关注的推广回答者:1\7*8*9+1/8*9*10+1/9*10*11+1/10*11*12_百度作业帮
1\7*8*9+1/8*9*10+1/9*10*11+1/10*11*12
1/7*8*9+1/8*9*10+1/9*10*11+1/10*11*12=(1/7*8-1/8*9+1/8*9-1/9*10+1/9*10-1/10*11+1/10*111/11*12)÷2=(1/7*8-1/11*12)÷2=(1/56-1/132)÷2=19/1848÷2=19/3696
您可能关注的推广回答者:1/8x9+1/9x10+1/10x11+.+1/99x100请问怎么解答?_百度作业帮
1/8x9+1/9x10+1/10x11+.+1/99x100请问怎么解答?
是1/(8x9)吧!1/(8x9)=(9-8)/(8x9)=9/(8x9)-8/(8x9)=1/8-1/9以此类推:1/(9x10)=1/9-1/101/(10x11)=1/10-1/11.1/(99x100)=1/99-1/100原式=1/8-1/9+1/9-1/10+1/10-1/11+...+1/99-1/100=1/8-1/100=23/2001/7×8+1/8×9+1/9×10+1/10×11……1/420_百度作业帮
1/7×8+1/8×9+1/9×10+1/10×11……1/420
1/7×8+1/8×9+1/9×10+1/10×11……1/420=(1/7-1/8)+(1/8-1/9)+(1/9-1/10)+(1/10-1/11)+……+(1/20-1/21)=1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11+……+1/20-1/21=1/7-1/21=2/21计算,(1/8+1/9+1/10+1/11)x(1/9+1/10+1/11+1/12)-(1/8+1/9+1/10+1/11+1/12)x(1/9+1/10+1/11)_百度作业帮
计算,(1/8+1/9+1/10+1/11)x(1/9+1/10+1/11+1/12)-(1/8+1/9+1/10+1/11+1/12)x(1/9+1/10+1/11)
设(1/8+1/9+1/10+1/11)=a,1/9+1/10+1/11=ba(b+1/12)-(a+1/12)*b=(a-b)/12=(1/8)/12=1/96

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