ln根号1 sinx的微积分xy x^2 y^3求微分dy

来源：蜘蛛抓取(WebSpider) 时间：2015-11-02 00:49 标签： 若x 0 y 0 且x 根号xy
导数微分,在的数字是平方,立方1.求曲线y=xlnx-x在x=e处的切线方程2.设Y=4X-5cos+e+ln5,求dy 3.设y=e.cosx求y’ 4.设Y=SIN(X-1),求dy 5.设2x-3y+xy=e求Y’_百度作业帮
导数微分,在的数字是平方,立方1.求曲线y=xlnx-x在x=e处的切线方程2.设Y=4X-5cos+e+ln5,求dy 3.设y=e.cosx求y’ 4.设Y=SIN(X-1),求dy 5.设2x-3y+xy=e求Y’
导数微分,在的数字是平方,立方1.求曲线y=xlnx-x在x=e处的切线方程2.设Y=4X-5cos+e+ln5,求dy 3.设y=e.cosx求y’ 4.设Y=SIN(X-1),求dy 5.设2x-3y+xy=e求Y’
1.y'=lnx+x*1/x-1=lnx,k=lne=1,切线方程为：y=x-e 2.y'=12x^2+5sinx+e^x,dy=(12x^2+5sinx+e^x)dx3.y'=(e^x)cosx-(e^x)sinx4.dy=y'dx=[cos(x^2-1)]*2xdx=2xcos(x^2-1)dx5.lny=x+y,lny-y=lnx ,y'/y-1=1/x ,y'= (1+1/x)y高数微分习题求下列各函数的微分dy(1)y=3x^2-ln 1/x(2)y=e^-x cosx设由下列方程确定y是x的函数,求dy(1)2x^2 y-xy^2 +y^3=0_百度作业帮
高数微分习题求下列各函数的微分dy(1)y=3x^2-ln 1/x(2)y=e^-x cosx设由下列方程确定y是x的函数,求dy(1)2x^2 y-xy^2 +y^3=0
高数微分习题求下列各函数的微分dy(1)y=3x^2-ln 1/x(2)y=e^-x cosx设由下列方程确定y是x的函数,求dy(1)2x^2 y-xy^2 +y^3=0
(1)y = 3x^2 - ln 1/x = 3x^2 + lnxdy = 6xdx + (1/x)dx=(6x + 1/x)dx(2)y = e^(-x)cosxdy = -e^(-x)cosxdx - e^(-x)sinxdx= -e^(-x)[cosx + sinx]dx(3)2x^2 y - xy^2 + y^3=04xydx + 2x^2dy - y^2dx - 2xydy + 3y^2dy = 0dy = [4xy - y^2]dx/[2xy - 3y^2 - 2x^2]= [(4x - y)y/(2xy - 3y^2 - 2x^2)]dx
(1)dy=6x+1/x(2)dy=sinxe^(-x)-cosxe^-x (3)dy=(y^2-4xy)/(2x^2+3y^2-2xy)微分方程(x^3+xy^2)dx+(x^2y+y^3)dy=0_百度作业帮
微分方程(x^3+xy^2)dx+(x^2y+y^3)dy=0
微分方程(x^3+xy^2)dx+(x^2y+y^3)dy=0
方程分离变量后两边积分得1/2ln(1+y^2)=1/2ln 1-x^2的绝对值+ln c1的绝对值。(x3 + xy2)dx + (x2y + y3)dy = 0x(x2 + y2) + y(x2 + y2)dy/dx = 0(x2 + y2)(x + ydy/dx) = 0x2 + y2 = 0 或 x + ydy/dx = 0y dy = -...微分方程的通解（xy^2+x）dx+（y-x^2y）dy=0。书上答案是（1+y^2）/（1-x^2）=C, 微分方程的通解（xy^2+x）dx+（
微分方程的通解（xy^2+x）dx+（y-x^2y）dy=0。书上答案是（1+y^2）/（1-x^2）=C
zxc2-12-20 微分方程的通解（xy^2+x）dx+（y-x^2y）dy=0。书上答案是（1+y^2）/（1-x^2）=C
（x^2-1）dx两边积分;（x^2-1）dx2y/（y^2+1）dy=2x&#47（xy^2+x）dx+（y-x^2y）dy=0x（y^2+1）dx=y（x^2-1）dyy&#47，得ln（y^2+1）=ln（x^2-1）＋lncy²＋1=c【x²-1】即（1+y^2）/（y^2+1）dy=x&#47
(x^2-1)=d(y^2+1)/(x^2-1)=d(y^2+1)/(1-x^2)=-ydy&#47（xy^2+x）dx+（y-x^2y）dy=0xdx(y^2+1)=-ydy(1-x^2)xdx/(x^2-1)]=lnC(y^2+1)/(1-x^2)=-d(y^2)/(y^2+1)d(x^2)/(y^2+1)dln(x^2-1)=dln(y^2+1)ln(x^2-1)=ln(y^2+1)-lnCln(y^2+1)-ln(x^2-1)=lnCln[(y^2+1)/(y^2+1)d(x^2-1)/(y^2+1)d(x^2)&#47z=x/根号下x^2+y^2,求全微分_百度作业帮
z=x/根号下x^2+y^2,求全微分
z=x/根号下x^2+y^2,求全微分
zx=[√（x²+y²）-x²/√（x²+y²）]/（x²+y²）=y²/(x²+y²)^(3/2)zy=[0×√（x²+y²）-xy/√（x²+y²）]/（x²+y²）=-xy/(x²+y²)^(3/2)所以dz=zxdx+zydy=y²/(x²+y²)^(3/2)dx-xy/(x²+y²)^(3/2)dy

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